4[2c+8]=5[c+4]

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Solution for 4[2c+8]=5[c+4] equation:


Simplifying
4[2c + 8] = 5[c + 4]

Reorder the terms:
4[8 + 2c] = 5[c + 4]
[8 * 4 + 2c * 4] = 5[c + 4]
[32 + 8c] = 5[c + 4]

Reorder the terms:
32 + 8c = 5[4 + c]
32 + 8c = [4 * 5 + c * 5]
32 + 8c = [20 + 5c]

Solving
32 + 8c = 20 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
32 + 8c + -5c = 20 + 5c + -5c

Combine like terms: 8c + -5c = 3c
32 + 3c = 20 + 5c + -5c

Combine like terms: 5c + -5c = 0
32 + 3c = 20 + 0
32 + 3c = 20

Add '-32' to each side of the equation.
32 + -32 + 3c = 20 + -32

Combine like terms: 32 + -32 = 0
0 + 3c = 20 + -32
3c = 20 + -32

Combine like terms: 20 + -32 = -12
3c = -12

Divide each side by '3'.
c = -4

Simplifying
c = -4

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